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Starting from rest, the road runner accelerates at 3 mi/s² for 10 seconds. How far does the road runner travel during the 10-second time interval?

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Final answer:

Using the kinematic equation for uniformly accelerated motion, we find that the road runner travels 150 miles in the 10-second time interval when accelerating from rest at 3 mi/s².

Step-by-step explanation:

The student is asking about the distance traveled by the road runner which accelerates from rest over a 10-second time interval. To calculate the distance, we can use the kinematic equation for uniformly accelerated motion:

d = ut + (1/2)at²

where d is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time. Since the road runner starts from rest, the initial velocity u is 0. Plugging in the given values, we get:

d = 0 mi/s × 10 s + (1/2)×3 mi/s²×10² s²

d = 0 + (1/2)×3×10²

d = 1.5×10²

d = 150 mi

The road runner travels 150 miles during the 10-second time interval.

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