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Find the distance between the two given points. O(-3,-2) and P(-3,4)​

1 Answer

7 votes

Answer:


\boxed {\boxed {\sf d= 6}}

Explanation:

Distance can be found using this formula:


d=\sqrt {(x_2-x_1)^2+(y_2-y_1)^2

Where (x₁, y₁) and (x₂, y₂) are the points.

We are given the points O (-3, -2) and P(-3,4). Therefore,


x_1= -3 \\y_1= -2 \\x_2= -3 \\y_2=4

Substitute the values into the formula.


d=\sqrt {(-3--3)^2+(4--2)^2

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction.

Solve inside the parentheses first.

  • (-3--3)= -3+3=0
  • (4--2)= 4+2=6


d= \sqrt {(0)^2+ (6)^2}

Solve the exponents.

  • (0)²= 0*0=0
  • (6)²= 6*6=36


d=\sqrt {0+36

Add.


d= \sqrt {36

Take the square root.


d=6

The distance is 6.

User Yashawant
by
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