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How does oxidative damage occur?

How does Vitamin E defend against this?

User Tgdavies
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Final answer:

Oxidative damage occurs when unstable free radicals interact with cellular components, and vitamin E protects against this damage by acting as an antioxidant, scavenging free radicals and preventing harmful chain reactions in cellular structures.

Step-by-step explanation:

Oxidative damage occurs when highly reactive molecules known as free radicals react with various cellular components such as DNA, proteins, and cell membranes, causing damage that can contribute to aging and diseases. These free radicals contain unpaired electrons, making them unstable and likely to engage in chemical reactions to achieve stability. Environmental factors such as radiation and pollution, as well as metabolic reactions involving oxygen, can lead to the formation of free radicals. Vitamin E, chemically known as tocopherol, is a potent antioxidant that protects against oxidative damage by scavenging free radicals. This vitamin is particularly effective in lipid environments, such as cell membranes made up of fatty acids. The tocopherols prevent cellular components from oxidative damage, which is a process where free radicals remove electrons from these molecules, potentially starting a harmful chain reaction. The protection mechanism of vitamin E involves the donating of a hydrogen atom from its structure to neutralize the free radicals. Although vitamin E itself becomes a free radical through this process, it is much less reactive and can be converted back to its original form through interaction with other antioxidants, such as vitamin C. By halting the destructive reaction cascades initiated by free radicals, vitamin E preserves the integrity of cell membranes and other cellular components.

User Tvsbrent
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