Question

A cannon shoots a shell up with an initial vertical velocity component of 10m/s and an initial horizontal component of 30m/s. Neglecting air resistance and the curvature of the Earth, how far away from the cannon will the shell hit?

Answer 1

The shell will hit a point approximately 61.2 meters away from the cannon.

Step-by-step explanation:

In order to find how far away from the cannon the shell will hit, we can analyze the vertical and horizontal motion of the projectile separately.

A projectile launched with an initial vertical velocity component of 10 m/s and an initial horizontal velocity component of 30 m/s will follow a parabolic trajectory due to gravity.

The time it takes for the shell to reach the ground can be determined using the equation:

t = 2 * (Vertical component of initial velocity) / acceleration due to gravity

Substituting the known values, we get:

t = 2 * 10 m/s / 9.8 m/s^2 = 2.04 s

Now we can calculate the horizontal distance traveled using the equation:

Distance = (Horizontal component of initial velocity) * time

Substituting the known values, we get:

Distance = 30 m/s * 2.04 s = 61.2 m

Therefore, the shell will hit a point approximately 61.2 meters away from the cannon.