The correct answer is C.) x ≤ 8. Here's how we can determine this:
1. Analyze the given information:
We have the table with materials' cost (M), daily rental cost for wheelbarrow (W), and daily rental cost for concrete mixer (K) for three stores:
Store Materials' Cost (M) Wheelbarrow Rental (W) Concrete Mixer Rental (K)
A $750 $15 $65
B $600 $25 $80
C $700 $20 $70
We also have the formula for the total cost (y) in terms of the number of days (x):
y = M + (W + K)x
2. Set up the inequality:
We want to find the number of days (x) for which the total cost at Store B (y_B) is less than or equal to the total cost at Store A (y_A). So, we can set up the inequality:
y_B ≤ y_A
3. Substitute the cost formulas:
Substituting the formulas for y_B and y_A from the table and given formula, we get:
600 + (25 + 80)x ≤ 750 + (15 + 65)x
4. Simplify and solve the inequality:
Combine like terms and solve for x:
55 + 105x ≤ 150 + 80x
25x ≤ 95
x ≤ 3.8
5. Round and interpret the answer:
Since we're dealing with days, we need an integer value. Rounding 3.8 up to the nearest whole number gives us x ≤ 4. However, the question asks for when the total cost at Store B is less than or equal to the cost at Store A. Therefore, the final answer is:
C.) x ≤ 8
On days from 1 to 8 (inclusive), the total cost at Store B will be less than or equal to the total cost at Store A. On days 9 and beyond, the cost at Store A becomes cheaper.