Final answer:
The other product of the nuclear reaction 53₂₄Cr + (₄/₂)He → 1n + ? is iron-56 (56₂₆Fe), determined by balancing the atomic and mass numbers in the nuclear equation.
Step-by-step explanation:
The other product of the nuclear reaction 53₂₄Cr + (₄/₂)He → 1n + ? is 56₂₆Fe. This is determined by balancing the nuclear equation, considering both the atomic numbers (protons) and mass numbers (nucleons - protons and neutrons). Chromium-52 has an atomic number of 24 and a mass number of 52, and helium-4 has an atomic number of 2 and a mass number of 4. When these react, they form a neutron (1n) with an atomic number of 0 and a mass number of 1, and another product which we need to identify.
To balance the equation, the unknown product must have the remaining mass and atomic numbers after subtracting the neutron produced. This gives us an atomic number of 26 and a mass number of 56, which corresponds to iron-56 (56₂₆Fe).