Question

HIV infects and destroys CD4 cells. List the following events in the order in which they occur.

1. Virus invades cell with CD4 antigen.
2. Viral RNA converts with reverse transcriptase to viral DNA.
3. Viral DNA integrates with host cell DNA.
4. Virus remains latent, or actively replicates.
5. Virus sheds protein coat.
A) 1, 2, 3, 4, 5
B) 2, 1, 3, 4, 5
C) 1, 2, 4, 3, 5
D) 2, 3, 1, 5, 4

Answer 1

The correct sequence for HIV infecting CD4 cells is 1, 2, 3, 4, 5, representing the virus's attachment to the cell, conversion of RNA to DNA, integration into the host genome, latent phase or active replication, and shedding of the protein coat.

Step-by-step explanation:

The correct order for the events that occur when HIV infects and destroys CD4 cells is as follows:

1. Virus invades cell with CD4 antigen.
2. Viral RNA converts with reverse transcriptase to viral DNA.
3. Viral DNA integrates with host cell DNA.
4. Virus remains latent, or actively replicates.
5. Virus sheds protein coat.

This sequence corresponds to the life cycle of HIV, where the virus first binds to the CD4 receptor on the T-cell's surface, enters the cell, and sheds its coat. Inside the cell, the reverse transcriptase enzyme converts the viral RNA into DNA, which is then integrated into the host's genome by integrase. The viral DNA can remain dormant or be actively transcribed, leading to the production of new viruses that bud from the cell's membrane.