Answer:
![((1)/(3)x - 3,-(1)/(3)y+2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3mlfizelcap7w47tnvwdutp95fakutvpyx.png)
Both triangles will be similar
Explanation:
See comment for complete question.
Given
Let the coordinates of the triangle be T(x,y)
First transformation: Dilation by 1/3
The new points will be:
![T' = (1)/(3)(x,y)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3ur1a7tunwxszifb9n078ekwlb67qe8rc0.png)
![T' = ((1)/(3)x,(1)/(3)y)](https://img.qammunity.org/2022/formulas/mathematics/high-school/xugs8m0apx7t534d66tninp85rws77e661.png)
Second: Reflection over the x-axis
When a point (x,y) is reflected over the x-axis, the new point is (x,-y).
So, we have:
![T'' = ((1)/(3)x,-(1)/(3)y)](https://img.qammunity.org/2022/formulas/mathematics/high-school/c4b5prfyncfxawaw7ftncegd41e8cbat9r.png)
Third: Translation 3 units left and 2 units up.
When a point (x,y) is translated b units left and h units up, the new point is (x - b,y+h).
In this case:
and
![h = 2](https://img.qammunity.org/2022/formulas/mathematics/high-school/vexfbeh77x22qvvu8t85apqdkr886xq5zy.png)
So, we have:
![T''' = ((1)/(3)x - 3,-(1)/(3)y+2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/czt0n7w4xla1xltt05fmyogmo8wkzdjd3n.png)
Hence, the coordinate of the new triangle will be:
![((1)/(3)x - 3,-(1)/(3)y+2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3mlfizelcap7w47tnvwdutp95fakutvpyx.png)
Additionally, both triangles will be similar because all the transformation done are rigid transformations i.e. Dilation, Reflection and Translation