Question

What is an equation of the line that passes through the points (-6, -2) and
(6,8)?

Answer 1

y=5/6x+b

Explanation:

use formula (y2-y1)/(x2-x1) to look for the slope:

(8-(-2))/(6-(-6))

=10/12

=5/6 (simplified)

then, use the formula y=mx+b to get the equation by substituting m and x, y to either (-6, -2) or (6, 8):

8=5/6(6)+b

8=5+b

3=b (subtract 5 on both sides)

equation:

y=5/6x+3