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6. A motivational speaker sells regular tickets and VIP tickets to their show. In order for the event to be profitable, it must sell a minimum of 80 VIP tickets and a minimum of 120 regular tickets. The speaker makes a profit of $225 for each regular ticket and a profit of $210 for each VIP ticket. The venue has room for 300 people. How many of each ticket should be sold to maximize profits?

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The motivational speaker should sell 180 regular tickets and 120 VIP tickets to maximize their profits while fulfilling the minimum ticket requirements and staying within the venue's capacity.

How can you solve how many of each ticket should be sold to maximize profits?

Let:

x = number of regular tickets sold

y = number of VIP tickets sold

2. Formulate the objective function:

We want to maximize the total profit. Therefore, the objective function is:

P(x, y) = 225x + 210y

Minimum VIP tickets: y ≥ 80

Minimum regular tickets: x ≥ 120

Maximum capacity: x + y ≤ 300

This is a linear programming problem. Using the analytical methods to find the feasible region and the point within it that maximizes the objective function.

we convert the constraints into equalities by introducing slack variables.

Formulate the Lagrangian function by adding the objective function and Lagrange multipliers multiplied by the constraints.

Take partial derivatives of the Lagrangian function with respect to x, y, and the Lagrange multipliers, and set them equal to zero.

Solving the system of equations obtained to find the optimal values of x, y, and the Lagrange multipliers.

Solution:

x = 180 regular tickets

y = 120 VIP tickets

Total profit: P(180, 120) = 225 * 180 + 210 * 120 = $63,900

Therefore, the motivational speaker should sell 180 regular tickets and 120 VIP tickets to maximize their profits while fulfilling the minimum ticket requirements and staying within the venue capacity.

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