Question

What output will this code produce when executed?

class Bob {
public:
Bob(int n) : hammer(n) { }
int hammer = 52;
};

int main() {
Bob b;
cout << b.hammer << '\\';
}
a) 0
b) 52
c) Compilation error
d) Runtime error

Answer 1

The code will produce the output 52 when executed.

Step-by-step explanation:

When the given code is executed, it will produce the output 52.
The class Bob has a member variable hammer with the initial value of 52. In the main function, an object of the class Bob is created without any arguments, so the constructor Bob(int n) is called with the default argument of 52, initializing the member variable hammer with the value 52. Finally, the value of hammer is printed using the cout statement, resulting in the output of 52.