Question

What will this code produce?

void foo(int bill) {
const int ted = bill;
cout << ted;
}

int main() {
foo(12);
foo(34);
}
A) 1212
B) 3434
C) 1234
D) 3432

Answer 1

The code produces the output '1234' by printing the values passed to the function 'foo' consecutively without any separators.

Step-by-step explanation:

The code in question is a simple C++ program that consists of a function named foo and the main function. When the foo function is called with an integer argument, it creates a constant integer ted and assigns the value of the parameter bill to it. Then, it prints the value of ted to the standard output.

When running the provided code, the output will be a sequence of the arguments passed to foo function without any space or newline character in between. Therefore, for the calls foo(12) and foo(34), the output will be:

1234

Since the code simply outputs the values one after the other, the correct answer to the question is:

C) 1234