Question

Bool rocket() {

static bool raccoon = groot();
return raccoon;
}
In this code, when will groot() be called?

a) During the first call to the rocket() function
b) Before the program starts
c) Every time the rocket() function is called
d) It will never be called

Answer 1

In the provided code, the function groot() is called during the first call to the rocket() function. This is due to the use of a static variable which is only initialized once, the first time the containing function is called.

Step-by-step explanation:

In the given code snippet, groot() will be called during the first call to the rocket() function. This is because the variable raccoon is declared as static inside the rocket() function. In C++ and similar languages, static variables inside a function are initialized only once, and that occurs the first time the function in which they are declared is called. Therefore, raccoon will be initialized by the return value of groot() the first time rocket() is called, and subsequent calls to rocket() will not call groot() again.