Final answer:
The frequency of vibrations for a tire with a crevice every 2 cm, while the car moves at 30 m/s, is 1500 Hz. This is because the frequency, which is vibrations per second, is calculated by dividing the car's speed by the distance between crevices.
Step-by-step explanation:
To calculate the frequency of the vibrations made by a tire with a tread pattern that has a crevice every 2.00 cm, we need to first understand the relation between the speed of the car, the distance between the crevices, and the frequency. The frequency (γ) is the number of times a repeating event occurs per unit time. In this case, each crevice causes a vibration as the tire rotates, so as the car moves, each crevice on the tire's surface will pass a fixed point and cause one vibration.
Given that the car is moving at 30.0 m/s, and there is a crevice every 2.00 cm (which is 0.02 meters), we can calculate how many crevices will pass a given point each second. This number will be the frequency.
Frequency is calculated as speed/distance, so we divide the car's speed by the distance between crevices:
30.0 m/s ÷ 0.02 m = 1500 vibrations per second, which is 1500 Hz (Hertz).
Therefore, the frequency of the vibrations is 1500 Hz when the car is moving at 30.0 m/s.