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Use the algebra of limits to find the limit of (2n^2 -5n +8)/3(n-2)^2

User Memoselyk
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Final answer:

To find the limit of (2n^2 - 5n + 8) / 3(n - 2)^2 as n approaches infinity, we simplify the expression by dividing by n^2 and ignoring lower-power terms, resulting in a limit of 2/3.

Step-by-step explanation:

The question involves finding the limit of the function (2n^2 - 5n + 8) / 3(n - 2)^2 as n tends to infinity, using the algebra of limits. To answer this question, we'll consider the highest powers of n in the numerator and the denominator.

Firstly, we recognize that as n approaches infinity, the terms with lower powers of n become negligible compared to the highest power term. So, we can simplify the expression by dividing the numerator and the denominator by n^2, the highest power of n in the expression.

This simplification yields:

(2 - 5/n + 8/n^2) / (3/n^2)(1 - 4/n + 4/n^2)

Because the terms with n in the denominator tend to zero as n approaches infinity, we are left with:

(2/3)

Therefore, the limit of the given function as n approaches infinity is 2/3.

User Prince Hamza
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