Question

Std::cout << srand(55) << '\\';

Answer 1

The given code is written in C++ and uses the srand() function to seed the random number generator. However, attempting to print the return value of srand(55) with std::cout will not display any useful information or random numbers.

Step-by-step explanation:

The given code is written in C++, which is a programming language used in computers and technology. It uses the srand() function to seed the random number generator. The number passed to srand() (in this case, 55) determines the starting point for the sequence of random numbers generated.

However, the code also attempts to print the return value of srand(55) with std::cout. The srand() function does not return a value, so printing it will not give any meaningful output. Therefore, the code will not display any useful information or random numbers.