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At the start of shift at 0700h, the PN is informed that the patient has 2/3 and 1/3 running at 125 cc/h, with 875 cc TBI. What time should the PN hang a new bag of 2/3 and 1/3?

User Banshi
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Final answer:

To determine when to hang a new IV bag, divide the total volume (875 cc) by the infusion rate (125 cc/h) to find the duration (7 hours). Adding 7 hours to the start time of 7:00 AM indicates that a new bag should be hung at 2:00 PM.

Step-by-step explanation:

The student's question pertains to calculating the time at which a new intravenous (IV) bag should be hung, given a current infusion rate and total bag infusion (TBI) volume. This type of problem involves arithmetic and understanding of rates, which is a fundamental concept in mathematics.

To calculate the time to hang a new bag of 2/3 and 1/3, we first need to determine how long the current bag will last. We are informed that the IV is running at a rate of 125 cc/h. With 875 cc TBI, we can divide the total volume by the rate to find the duration in hours that the bag will last:

Duration = Total Volume / Rate

Duration = 875 cc / 125 cc/h = 7 hours

Since the shift starts at 0700h (7:00 AM), adding 7 hours to this start time gives us the time the new bag should be hung:

New Bag Time = 7:00 AM + 7 hours = 2:00 PM

Therefore, the PN should hang a new bag at 2:00 PM.

User Furqan Asghar
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