Final answer:
Combinations of 6(1) and 6(2) status can be calculated using the formula C(n, k) = n! / (k!(n-k)!), where n is the total number of items in the set and k is the number of items we are selecting. In this case, there are 6 different combinations when selecting 1 item and 15 different combinations when selecting 2 items from a set of 6.
Step-by-step explanation:
Combinations of 6(1) and 6(2) status can be understood in the context of permutations and combinations in mathematics.
When we have a set of 6 items and we are selecting 1 or 2 from that set, we are dealing with combinations. The number of combinations can be calculated using the formula C(n, k) = n! / (k!(n-k)!), where n is the total number of items in the set and k is the number of items we are selecting.
In this case, we have a set of 6 items and we are selecting either 1 or 2 items. Let's calculate the combinations:
- For selecting 1 item from 6, the number of combinations is C(6, 1) = 6! / (1!(6-1)!) = 6.
- For selecting 2 items from 6, the number of combinations is C(6, 2) = 6! / (2!(6-2)!) = 15.
Therefore, there are 6 different combinations when selecting 1 item and 15 different combinations when selecting 2 items from a set of 6.