Question

Find the equation of a line passing through the point(-3,0) and (2,-3)​

Answer 1

y = -3

Explanation:

Answer 2

Answer (assuming the question allows it to be written in slope-intercept form):

`y = -(3)/(5) x-(9)/(5)`

Explanation:

1) First, find the slope of the equation. Use the slope formula
`m = (y_2-y_1)/(x_2-x_1)`, substitute the given points' x and y values, and simplify:

`m = ((-3)-(0))/((2)-(-3)) \\m =(-3-0)/(2+3)\\m = -(3)/(5)`

Thus, the slope is
`-(3)/(5)`.

2) Now, use the point-slope formula
`y-y_1 = m (x-x_1)` and substitute real values for
`m`,
`x_1`, and
`y_1`.

Since
`m` represents the slope, substitute
`-(3)/(5)` in its place. Since
`x_1` and
`y_1` represent the x and y values of a point the line crosses, use the x and y values of any one of the given points to substitute into the formula. (Either one is fine. I chose (2,-3).) Then, isolate y to put it into slope-intercept form and find the answer:

`y-(-3) = -(3)/(5) (x-(2))\\y + 3 = -(3)/(5) x + (6)/(5) \\y = -(3)/(5) x - (9)/(5)`