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A pure inductor is connected to an ac power supply. In this circuit, the current

A) leads the voltage by 90°.

B) is in phase with the voltage.

C) lags the voltage by 45°.

D) lags the voltage by 90°.

E) leads the voltage by 45°.

User Ben Davis
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1 Answer

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Final answer:

In an AC circuit with a pure inductor, the voltage leads the current by 90°.

Step-by-step explanation:

When a sinusoidal voltage is applied to a pure inductor in an AC circuit, the voltage leads the current by 90°. This means that the current lags behind the voltage by 90°.

In other words, the current waveform reaches its peak 1/4 cycle after the voltage waveform reaches its peak.

This phase relationship between voltage and current in a pure inductor is a characteristic of inductance.

User Basit Ali
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