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Zane claims that every equation has exactly one solution. Select all equations that disprove Zane’s claim.
1. 7x = 4x
2. 2(2x + 3) = 4(x + 1)
3. 7 + 3x = 4(2 + 3/4x)
4. 2x + 11 = 25
5. 8(2 + x) = 17

User Alisher
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2 Answers

29 votes
29 votes

Answer:

The equations that disprove Zane's claim are:

1) 7x = 4x has no solution because the left and right sides of the equation are not equal.

2) 2(2x + 3) = 4(x + 1) has infinite solutions because the left and right sides of the equation are equal for all values of x.

3) 7 + 3x = 4(2 + 3/4x) has no solution because the left and right sides of the equation are not equal.

4) 8(2 + x) = 17 has infinite solutions because the left and right sides of the equation are equal for all values of x.

Therefore, Zane's claim that every equation has exactly one solution is disproven by these equations.

User Zhenyi Zhang
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2.7k points
16 votes
16 votes

Answer:

All of the equations listed disprove Zane's claim that every equation has exactly one solution. Equation 1 (7x = 4x) has no solutions because the left and right sides of the equation are not equal. Equation 2 (2(2x + 3) = 4(x + 1)) has exactly one solution because the left and right sides of the equation are equal for one value of x. Equation 3 (7 + 3x = 4(2 + 3/4x)) has no solutions because the left and right sides of the equation are not equal for any value of x. Equation 4 (2x + 11 = 25) has exactly one solution because the left and right sides of the equation are equal for one value of x. Equation 5 (8(2 + x) = 17) has no solutions because the left and right sides of the equation are not equal for any value of x. Therefore, all of the equations listed disprove Zane's claim that every equation has exactly one solution.

User Tekkub
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3.6k points
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