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An outfielder throws a baseball to home plate with a velocity of 27 m/s at 35o. It is caught by the first baseman. How long was it in the air

User Azhy
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1 Answer

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Final answer:

The time of flight of the baseball was 0 seconds.

Step-by-step explanation:

To find the time of flight of the baseball, we can use the equation of motion for horizontal motion: d = vxt, where d is the horizontal distance, vx is the horizontal component of velocity, and t is the time of flight. In this case, we are given the values of d = 0 m (since the baseball was caught at home plate), and vx = 27 m/s cos(35°). Solving for t, we have:



t = d / vx = 0 / (27 m/s cos(35°))



In this case, the ball was caught at home plate, so the horizontal distance is 0 meters. Therefore, the time of flight is 0 seconds.

User Binarus
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