Answer:
The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope of the line and b is the y-intercept (the point where the line crosses the y-axis).
In this case, we are given the point (5, -2) and the slope -2/5, so we can plug these values into the equation to find the y-intercept b:
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-2 = (-2/5) * 5 + b
-2 = -2 + b
b = 0
Therefore, the y-intercept of the line is 0, and the equation of the line is y = (-2/5)x + 0, or y = -2/5x.