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Vertex: (-1/2, -25/4)
yint: (0, -6)
aos: x = -1/2
roots: (-3,0)(2,0)
opening: up

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Answer:

The quadratic equation or function represented by the given information has a vertex at (-1/2, -25/4), a y-intercept at (0, -6), an axis of symmetry at x = -1/2, x-intercepts at (-3, 0) and (2, 0), and opens upwards.

Step-by-step explanation:

Based on the given information, the following characteristics can be identified for the quadratic equation or function:

1. Vertex: The vertex of the parabola is located at (-1/2, -25/4). This means that the parabola is symmetric and opens either upwards or downwards.

2. Y-intercept: The y-intercept of the parabola is at the point (0, -6). This means that the parabola intersects the y-axis at this point.

3. Axis of symmetry: The axis of symmetry of the parabola is the vertical line x = -1/2. This line divides the parabola into two symmetrical halves.

4. Roots or x-intercepts: The parabola intersects the x-axis at the points (-3, 0) and (2, 0). These are the values of x where the parabola intersects the x-axis, also known as the roots or x-intercepts.

5. Opening: The given information states that the parabola opens upwards. This means that the coefficient of the leading term (the x^2 term) in the quadratic equation is positive.

User Johnmerm
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