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A submarine travels 12 km due West from its base and then turns and travels due South for 14.8 km. How far away is the submarine from its base? .

User DWX
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2 Answers

6 votes

Answer:

The answer is 19.1

Explanation:


z = \sqrt{ {x}^(2) + {y}^(2) } = \sqrt{ {12}^(2) + {14.8}^(2) } = 19.1

User Jgritty
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7 votes

Answer:

the submarine travels 26.8 km. from its base

User Karem
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