Question

If x = t^3 and y = t^2 - 2 , what is y in terms of x?

Answer 1

E

Explanation:

You have to get t^2 in the first equation.

x = t^3 Take the cube root of both sides

`\sqrt[3]{x} = \sqrt[3]{t^3}`

`\sqrt[3]{x}=t` Now square both sides

`(\sqrt[3]{x})^2 = t^2`

`x^(2)/(3) = t^2`

Now you can substitute into the second equation

y = t^2 - 2

y =
`x^(2)/(3)` - 2

E