Final answer:
The maximum length of secondary circuit wire in a remote transformer channel letter setup depends on the power dissipation capabilities of the wire and the allowed power loss based on the required power of the neon lamps.
Step-by-step explanation:
The largest length of secondary circuit wire (GTO) in flexible metal conduit that can be utilized from a transformer to the first neon tube electrode in a remote transformer channel letter setup depends on the voltage requirement and the power dissipation of the neon lamps. Although the provided information does not specify these values, we can use the concept of power transmission to approximate the maximum length.
Power can be calculated using the formula: P = IV, where P is power, I is current, and V is voltage. The primary winding of the transformer has a fuse that goes off at 0.5 A, so the maximum current the neon lamps can draw is 0.5 A. Given that the voltage required for neon signs is typically 12 kV, we can calculate the maximum power using the formula: P = (0.5 A) x (12,000 V) = 6,000 W.
Since power loss in a wire can be represented by the formula: P_loss = I^2R, where P_loss is power loss, I is current, and R is resistance, we can approximate the maximum length by equating the power loss to the maximum power dissipation. However, without information about the specific resistance of the wire, we cannot provide an exact numerical value for the maximum length. We can only state that the maximum length of secondary circuit wire would be limited by the power dissipation capabilities of the wire and the allowed power loss based on the provided power requirement.