Question

A race car moves around a circular track. The centripetal force acting on the car is 10,000 N. If the track has a radius of 72 m, and the mass of the car is 800 kg, what is the tangential speed of the car as it moves around the track?

Answer 1

The tangential speed of the car as it moves around the track is 33.5 m/s.

Step-by-step explanation:

To find the tangential speed of the car, we need to use the equation for centripetal force:

F = mv^2 / r

In this equation, F is the centripetal force, m is the mass of the object, v is the tangential speed, and r is the radius of the circular path. In this case, we know that F = 10,000 N, m = 800 kg, and r = 72 m. We can solve for v by rearranging the equation to solve for v:

v = sqrt(Fr / m)

Substituting the given values into this equation, we get:

v = sqrt((10,000 N * 72 m) / 800 kg)

= sqrt((720,000 N * m) / 800 kg)

= sqrt((900,000 N * m) / 800 kg)

= sqrt(1125 N * m / 100 kg)

= sqrt(11.25 N * m / 1 kg)

= sqrt(11.25 N * m)

= 33.5 m/s

Therefore, the tangential speed of the car as it moves around the track is 33.5 m/s.