Answer:
The tangential speed of the car as it moves around the track is 33.5 m/s.
Step-by-step explanation:
To find the tangential speed of the car, we need to use the equation for centripetal force:
F = mv^2 / r
In this equation, F is the centripetal force, m is the mass of the object, v is the tangential speed, and r is the radius of the circular path. In this case, we know that F = 10,000 N, m = 800 kg, and r = 72 m. We can solve for v by rearranging the equation to solve for v:
v = sqrt(Fr / m)
Substituting the given values into this equation, we get:
v = sqrt((10,000 N * 72 m) / 800 kg)
= sqrt((720,000 N * m) / 800 kg)
= sqrt((900,000 N * m) / 800 kg)
= sqrt(1125 N * m / 100 kg)
= sqrt(11.25 N * m / 1 kg)
= sqrt(11.25 N * m)
= 33.5 m/s
Therefore, the tangential speed of the car as it moves around the track is 33.5 m/s.