Answer:
The expression you've provided is a sigma notation for the sum of a sequence. In this case, the expression is:
4Σ(+2)(r + 2) evaluated for r starting from 1.
This means we start with r=1 and continue up to some value (let's say n) and add up the values of (+2)(r + 2) for each value of r from 1 to n.
Let's calculate it step by step:
When r=1, the value of (+2)(r + 2) = (+2)(1 + 2) = 3*2 = 6
When r=2, the value of (+2)(r + 2) = (+2)(2 + 2) = 4*2 = 8
When r=3, the value of (+2)(r + 2) = (+2)(3 + 2) = 5*2 = 10
Adding them up: 6 + 8 + 10 = 24
So, 4Σ(+2)(r + 2) r=1 is equal to 24.