Question

X^2+10x+22=13 1. Rewrite the equation by completing the square your equation should look like (x+c)^2 = d or (x-c)^2=d 2. What was the solution to the equation?

Answer 1

(x+5)² = 16

Solution: -1 and -9

Explanation:

Given the quadratic equation X^2+10x+22=13

Subtract 22 from both sides

X^2+10x+22-22=13-22

x^2+10x = -9

Complete the square

Add the square of half of coefficient of x to both sides

coefficient of x = 10

half of coefficient of x = 10/2 = 5

square of half of coefficient of x= 5² = 25

Add 25 to both sides

x²+10x + 25 = -9+25

(x+5)² = 16

Hence the required equation is (x+5)² = 16

(x+5)² = 16

square root both sides

√(x+5)² = √16

x+5 = √16

x +5 = ±4

x = +4 - 5 and -4-5

x = -1 and -9

Hence the solution to the equation is -1 and -9