Question

a driver drives to depth of 20cm below the surface of water of density 1.0x10 cubed km3 the pressure he experiences isNm-2​

Answer 1

`20.61* 10^(5)Nm^(-2)`

Step-by-step explanation:

We are given that

h=20 cm=0.20m

1m=100 cm

Density of water=
`\rho=1.0* 10^3 kg/m^3`

We have to find the pressure experienced by driver at that depth.

Atmospheric pressure, P0=101 kPa

Pressure experience by driver

`P=\rho hg+P_0`

Where
`g=9.8`

`P=1.0* 10^3* 0.20* 9.8+101`

`P=2061KPa`

1 KPa=
`1000Nm^(-2)`

`P=2061* 1000=2061000N/m^2`

`P=20.61* 10^(5)Nm^(-2)`