Final answer:
To accomplish the jump between the two buildings, the stunt person must have a minimum horizontal velocity of approximately 2.94 m/s.
Step-by-step explanation:
To calculate the minimum horizontal velocity the stunt person must have to accomplish the jump, we can use the concept of projectile motion. The horizontal distance between the two buildings is 3 meters, and the vertical distance is 5 meters. We can use the formula v = d / t where v is the horizontal velocity, d is the horizontal distance, and t is the time taken.
First, we need to find the time taken for the object to fall 5 meters vertically. We can use the formula h = (1/2)gt² where h is the vertical distance, g is the acceleration due to gravity (9.8 m/s²), and t is the time taken. Plugging in the values, we get 5 = (1/2)(9.8)t². Solving for t, we find t ≈ 1.02 s.
Next, we can substitute the value of t into the formula v = d / t. Plugging in the values, we get v = 3 / 1.02 ≈ 2.94 m/s. Therefore, the minimum horizontal velocity the stunt person must have to accomplish the jump is approximately 2.94 m/s.