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13 votes
5. A ladder 17 m long reaches the window of a building 15 m above

the ground. Find the distance of the foot of the ladder from the
building
Hint. Let AB be the ladder, CB be the building and B be the
window.
15 m
Then, AB = 17 cm, BC = 15 m, find AC.)


User JMHNilbog
by
8.2k points

1 Answer

8 votes

Answer:

8 m.

Explanation:

Use the Pythagoras theorem

17^2 = 15^2 + AC^2

AC^2 = (17-15)(17+15) = 2 * 32

AC^2 = 64

AC = 8 m.

User Aravvn
by
7.7k points

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