Question

What will the code below output to the console and why ?

(1 + "2" + "2");
(1 + +"2" + "2");
(1 + -"1" + "2");
(+"1" + "1" + "2");
( "A" - "B" + "2");
( "A" - "B" + 2);

Answer 1

The code will output different results depending on the operations performed. The numbers and strings are treated differently based on the operators used.

Step-by-step explanation:

Answer:

1. (1 + "2" + "2") = "122". In this case, the numbers are treated as strings and concatenated together.
   
2. (1 + +"2" + "2") = "32". The unary plus operator (+) before the second "2" converts it into a number, so the addition operation takes place.
   
3. (1 + -"1" + "2") = "02". The unary minus operator (-) before the second "1" converts it into a number, and the addition of a number to a string results in string concatenation.
   
4. (+"1" + "1" + "2") = "112". The unary plus operator before the first "1" converts it into a number, and the addition of numbers results in arithmetic addition.
   
5. ("A" - "B" + "2") = "NaN2". The subtraction of two non-numeric strings results in a value called NaN (Not a Number).
   
6. ("A" - "B" + 2) = "NaN". The subtraction of two non-numeric strings followed by adding a number still results in NaN.