65.4k views
0 votes
A gas container is initially at 47.0 mm Hg and 77.0 K. What will the pressure be when the container warms up to room temperature of 25 ˚C?

A) 182 mm Hg
B) 25 mm Hg
C) 47 mm Hg
D) 760 mm Hg

User Oleschri
by
8.0k points

1 Answer

3 votes

Final answer:

The pressure of the gas will be 182 mm Hg when the container warms up to room temperature.

Step-by-step explanation:

The pressure of a gas can be determined using the ideal gas law, which states that pressure is directly proportional to temperature. When the temperature of a gas increases, its pressure also increases. In this scenario, the gas container initially has a pressure of 47.0 mm Hg and a temperature of 77.0 K. When the container warms up to room temperature of 25 ˚C (298 K), the pressure will increase. The final pressure can be calculated using the formula:

P1/T1 = P2/T2

Substituting the given values:

P2 = P1 * (T2 / T1)

P2 = 47.0 mm Hg * (298 K / 77.0 K)

P2 = 182 mm Hg

User Metacubed
by
8.2k points