Question

What is the concentration of HCl in a titration where 25mL of 0.2M NaOH neutralizes 20mL of HCl?

A) 0.1M
B) 0.2M
C) 0.25M
D) 0.4M

Answer 1

The concentration of HCl in the titration is 0.25M.

Step-by-step explanation:

In a neutralization reaction between an acid and a base, the moles of H+ ions from the acid would be equal to the moles of OH- ions from the base. From the given information, we can determine the moles of HCl and NaOH:

Moles of NaOH = volume (L) x concentration (M) = 0.025 L x 0.2 M = 0.005 mol NaOH

Since the balanced chemical equation for the neutralization reaction between HCl and NaOH is:

HCl + NaOH → H2O + NaCl

we can see that 1 mol of NaOH reacts with 1 mol of HCl. Therefore, the concentration of HCl is 0.005 mol HCl / 0.02 L = 0.25 M.