Final answer:
The mass of water in a calorimetry experiment where 0.145J of heat causes a 0.475°C temperature increase is calculated using the specific heat capacity of water. The result is approximately 0.076 grams, which is answer choice C.
Step-by-step explanation:
To calculate the mass of water present in a calorimetry experiment where 0.145J of heat causes a 0.475°C temperature change, we use the formula for heat transfer: q = mcΔT, where q is the amount of heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
The specific heat capacity of water is about 4.184 J/g °C. Therefore, rearranging the formula to solve for m gives us m = q / (cΔT). Substituting the given values:
m = 0.145 J / (4.184 J/g °C × 0.475 °C)
After the calculation, we find that the mass of the water is approximately 0.076 grams, which corresponds to answer choice C.