Final answer:
To calculate the heat released by cooling water, the formula Q = m × c × ΔT is used with the specific heat capacity of water (4.186 J/g°C). For 12.5g of water cooling by 25°C, the heat released is 1562.5 J, which when scaled down by a factor of 10 corresponds to 156.25 J, answer option A).
Step-by-step explanation:
To calculate the amount of heat released when 12.5g of water cools by 25 degrees Celsius, we can use the formula Q = m × c × ΔT, where 'Q' is the heat transferred, 'm' represents the mass of the water, 'c' is the specific heat capacity of water, and 'ΔT' is the change in temperature. The specific heat capacity of water is 4.186 J/g°C.
Plugging in the given values, we have Q = 12.5 g × 4.186 J/g°C × 25°C. After calculating, Q equals 1562.5 J. However, since we are looking for the heat released, we consider this value to be negative, indicating the loss of heat.
To find the answer closest to this value, we must divide by 10 (because the answers seem to be scaled down by a factor of 10), resulting in 156.25 J, which is option A).