Final answer:
The numbers will be logged in the order: 1, 4, 3, 2
Step-by-step explanation:
The numbers 1-4 will be logged to the console in the following order: 1, 4, 3, 2.
This is because the code is using setTimeout() function to delay the execution of certain blocks of code. The number 1 is logged immediately. The number 4 is logged next since it is not delayed. The number 3 is logged after a delay of 0 milliseconds, but it still needs to wait for the current execution to finish before being logged. Finally, the number 2 is logged after a delay of 1000 milliseconds.
In summary, even though the delay for number 3 is 0 milliseconds, it still needs to wait for the current execution to finish before being logged.