Final answer:
The alcohol and carboxylic acid that make the ester n-propyl propanoate are propanol and propanoic acid.
Step-by-step explanation:
The correct answer is (c) Propanol and propanoic acid.
Esters are formed by the reaction of an alcohol with a carboxylic acid. In this case, n-propyl propanoate is formed by the reaction of propanol (an alcohol) with propanoic acid (a carboxylic acid).