Final answer:
A ton of ice can provide cooling by absorbing heat from its surroundings and melting into water. The amount of cooling can be calculated using the heat of fusion and specific heat capacity of ice.
Step-by-step explanation:
A ton of ice can provide cooling by absorbing the heat from its surroundings and melting into water. The amount of cooling provided by a ton of ice can be calculated based on the amount of heat energy required to melt the ice. The specific heat capacity of ice is 2.09 J/g°C, and the heat of fusion for ice is 334 J/g. Assuming that all the ice melts, the amount of heat energy transferred can be calculated as follows:
- Convert the mass of the ice into grams. Since a ton is equal to 1000 kg, a ton of ice is equal to 1000,000 grams.
- Calculate the heat energy required to raise the temperature of the ice from 0°C to its melting point, which is 0°C. This can be calculated using the formula Q = m * c * ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
- Calculate the heat energy required to melt the ice by multiplying the mass of the ice by the heat of fusion.
- Add the heat energy required for raising the temperature and melting the ice to find the total heat energy transferred.
By following these steps, you can determine how much cooling a ton of ice can provide in 24 hours.