Question

The density of an irregular object is 47.94 lb per qt. The object is immersed in a beaker containing water. The mass of the object is equal to the mass of 12 cubes with a density of 6.00 g/mL and with dimensions of .900 inch x .900 inch x .900 inch. How much was the water displaced?

A. 1094.8685857321654 mL
B. 216 mL
C. 1296 mL
D. 951 mL

Answer 1

The volume of the water displaced by the object is 0.151 qt.

Step-by-step explanation:

To find the volume of the irregular object, we need to find the volume of the 12 cubes with known dimensions. The volume of each cube is calculated by multiplying the length, width, and height. Therefore, the volume of each cube is 0.900 in x 0.900 in x 0.900 in = 0.729 in³.

The total volume of the 12 cubes is then 0.729 in³ x 12 = 8.748 in³.

Since 1 qt is equal to 57.75 in³, the volume of the water displaced is 8.748 in³ / 57.75 in³/qt = 0.151 qt.