Question

Given the following printf statements:

printf("%03d", 0);
printf("%03d", 1);
printf("%03d", 123456789);
printf("%03d", -10);
printf("%03d", -123456789);

What will be printed for each of these statements?

Answer 1

Each printf statement with format specifier %03d outputs integers with a width of at least three characters, padding with zeroes where necessary. For integers less than three digits, zeroes are added, while longer integers are printed as-is. The output varies depending on the input integer's length and sign.

Step-by-step explanation:

The student's question pertains to the output of five printf statements in C programming using the format specifier %03d. This specifier is designed to print an integer in at least three digits, padding with zeroes if necessary.

• For printf("%03d", 0); the output will be 000 because the number has fewer than three digits and will be left-padded with zeroes.
• For printf("%03d", 1); the output will be 001 for the same reason as above.
• For printf("%03d", 123456789); the output will be 123456789 because the number exceeds three digits, so no padding is needed.
• For printf("%03d", -10); the output will be -010. Negative numbers are also padded, but the sign is kept.
• For printf("%03d", -123456789); the output will be -123456789 and as with large positive numbers, large negative numbers are printed as-is without padding.