Question

What will the following code output and why?

var b = 1;
function outer(){
var b = 2
function inner(){
b++;
var b = 3;
(b)
}
inner();
}
outer();

Answer 1

The output of the code will be undefined.

Step-by-step explanation:

The code will output undefined.

When the code is executed, the variable b is initialized with the value 1. Inside the function outer(), a new variable b is declared and assigned the value 2. Then, inside the function inner(), a new variable b is declared and assigned the value 3. However, before this assignment, the line b++; is executed. Since b has not been assigned a value yet, it is undefined at this point. Therefore, the output of this code is undefined.