Final answer:
The given information suggests that it would be surprising for it to take less than one minute to find a parking space. This can be determined by calculating the z-score and comparing it to the standard normal distribution.
Step-by-step explanation:
The length of time it takes to find a parking space at 9 a.m. follows a normal distribution with a mean of five minutes and a standard deviation of two minutes. To determine if it would be surprising for it to take less than one minute to find a parking space, we can calculate the z-score and compare it to the standard normal distribution.
- Calculate the z-score using the formula: z = (x - mean) / standard deviation. In this case, x = 1, mean = 5, and standard deviation = 2. Therefore, z = (1 - 5) / 2 = -2 / 2 = -1.
- Look up the z-score in the z-table or use a calculator to find the probability. A z-score of -1 corresponds to a probability of approximately 0.1587.
- Since the probability of finding a parking space in less than one minute (or 0 minutes) is less than 0.1587, it would be surprising if it took less than one minute to find a parking space.