Question

I'd like some help in these two questions please, thankyou so much. have a great day! stay safe and stay happy. (there are two parts of one question so uh yea.

Answer 1

The resultant force is 25 N in the negative x-direction.

Step-by-step explanation:

We need to find the total force in the x and y-direction and then the resultant force will be the magnitude of the sum of Fx and Fy.

Total force in the x-direction:

`F_(x)=12-37=-25\: N`

Total force in the y-direction:

`F_(y)=10-10=0\: N`

Therefore, the magnitude of the resultant force will be:

`F_(R)=\sqrt{F_(x)^(2)+F_(y)^(2)}`

`F_(R)=\sqrt{(-25)^(2)+0}`

`|F_(R)|=25\: N`

The resultant force is 25 N in the negative x-direction, in other words, the car will move to the left.

I hope it helps you!