Final answer:
The probability of getting at most 2 tails when a fair coin is tossed 9 times is approximately 0.090.
Step-by-step explanation:
To find the probability of getting at most 2 tails when a fair coin is tossed 9 times, we need to consider the possible outcomes and their probabilities.
There are a total of 2^9 = 512 possible outcomes when tossing a fair coin 9 times. To find the probability of getting at most 2 tails, we need to calculate the sum of the probabilities of getting 0, 1, or 2 tails.
The probability of getting 0 tails is (1/2)^9 = 1/512. The probability of getting 1 tail is 9/512, and the probability of getting 2 tails is 36/512. Adding these probabilities together gives us a probability of (1/512) + (9/512) + (36/512) = 46/512 = 0.08984
Therefore, the probability of getting at most 2 tails when a fair coin is tossed 9 times is approximately 0.090.