Question

M/s

3. A ferryboat accelerates from rest at a rate of 0.500 m/s2.
a. What is the velocity of the boat after it has traveled 4.75 m?
b. What is the velocity if the boat has traveled 50 m?

Answer 1

a. Final velocity, V = 2.179 m/s.

b. Final velocity, V = 7.071 m/s.

Step-by-step explanation:

Given the following data;

Acceleration = 0.500m/s²

a. To find the velocity of the boat after it has traveled 4.75 m

Since it started from rest, initial velocity is equal to 0m/s.

Now, we would use the third equation of motion to find the final velocity.

`V^(2) = U^(2) + 2aS`

Where;

• V represents the final velocity measured in meter per seconds.
• U represents the initial velocity measured in meter per seconds.
• a represents acceleration measured in meters per seconds square.
• S represents the displacement measured in meters.

Substituting into the equation, we have;

`V^(2) = 0^(2) + 2*0.500*4.75`

`V^(2) = 4.75`

Taking the square root, we have;

`V^(2) = \sqrt {4.75}`

Final velocity, V = 2.179 m/s.

b. To find the velocity if the boat has traveled 50 m.

`V^(2) = 0^(2) + 2*0.500*50`

`V^(2) = 50`

Taking the square root, we have;

`V^(2) = \sqrt {50}`

Final velocity, V = 7.071 m/s.