Final answer:
To remove the Nth node from the end of a linked list, use a two-pointer approach to traverse the list with a single pass and modify the next pointers to exclude the target node.
Step-by-step explanation:
Removing the Nth Node from End of a Linked List
To remove the Nth node from the end of a linked list, you need to follow a two-pointer approach. This includes initializing two pointers, often called fast and slow. The fast pointer advances the list by N+1 nodes first, and then both pointers advance together until the fast pointer reaches the end of the list. At this point, the slow pointer will be just before the Nth node from the end, and you can modify the next pointers to remove the desired node.
An example of this algorithm in a singly linked list is as follows:
Move the fast pointer N+1 nodes ahead in the list.
Move both fast and slow pointers one node at a time until the fast pointer reaches the end.
Remove the node after the slow pointer, which is the Nth node from the end.
This method efficiently removes the Nth node from the end with a single pass through the list, which is important for time complexity considerations.